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2x^2-56x-58.48=0
a = 2; b = -56; c = -58.48;
Δ = b2-4ac
Δ = -562-4·2·(-58.48)
Δ = 3603.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-\sqrt{3603.84}}{2*2}=\frac{56-\sqrt{3603.84}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+\sqrt{3603.84}}{2*2}=\frac{56+\sqrt{3603.84}}{4} $
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